SOLUTION: Use the laws of logarithms to rewrite each expression as a single logarithm, do NOT evaluate. 1) log 4 + log 25 2)log(little 2) 4 - log (little 2) 2 3)4log(little 4) 2 Ev

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Use the laws of logarithms to rewrite each expression as a single logarithm, do NOT evaluate. 1) log 4 + log 25 2)log(little 2) 4 - log (little 2) 2 3)4log(little 4) 2 Ev      Log On


   

Question 797632: Use the laws of logarithms to rewrite each expression as a single logarithm, do NOT evaluate.
1) log 4 + log 25
2)log(little 2) 4 - log (little 2) 2
3)4log(little 4) 2
Evaluate your answers from problems above, show your setups (b^k=n).
1) evaluate solution to problem 1.
2)Evaluate solution to problem 2.
3) evaliate solution to problem 3.
4)5^x= 100 solve for x using logarithms (round to 3 decimal places.)
Found 2 solutions by lwsshak3, Alan3354:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Use the laws of logarithms to rewrite each expression as a single logarithm, do NOT evaluate.
1) log 4 + log 25
=log(4*25)
=log(100)
..
2)log(little 2) 4 - log (little 2) 2
log%282%2C%284%29%29-log%282%2C%282%29%29=log%282%2C%284%2F2%29%29=log%282%2C%282%29%29
..
3)4log(little 4) 2
4log%284%2C%282%29%29=log%284%2C%282%5E4%29%29=log%284%2C%2816%29%29
..
Evaluate your answers from problems above, show your setups (b^k=n).
1) evaluate solution to problem 1.log(100)=2
2)Evaluate solution to problem 2.log%282%2C%282%29%29=1
3) evaliate solution to problem 3.log%284%2C%2816%29%29=4
4)5^x= 100 solve for x using logarithms (round to 3 decimal places.)
xlog(5)=log(100)
x=log(100)/log(5)=2/log(5)≈2.861

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The other tutor did all the rest, but
3) evaliate solution to problem 3.
log%284%2C16%29+=+2