SOLUTION: Two cyclists start biking from a trail’s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles
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Question 79762: Two cyclists start biking from a trail’s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Two cyclists start biking from a trail’s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
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Let t = time the 2nd cyclist is on the road when he catches up
Then (t+3) = time the 1st cyclist is on the road.
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When the 2nd cyclist catches up with the 1st, we know they will have traveled the same distance.
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Write a distance equation: Distance = speed * time
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10t = 6(t+3)
10t = 6t + 18
10t - 6t = 18
4t = 18
t = 18/4
t = 4.5 hrs (time of the 2nd cyclist:
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Then the 1st cyclist time = 7.5 hrs
Check to see if both traveled the same distance
4.5(10) = 45 mi
7.5(6) = 45 mi also
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Make sense to you, not that hard, right?
