SOLUTION: Solve log10(3x + 2) – 2log10x = 1 – log10(5x – 3)
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Question 797293
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Solve log10(3x + 2) – 2log10x = 1 – log10(5x – 3)
Answer by
lwsshak3(11628)
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Solve log10(3x + 2) – 2log10x = 1 – log10(5x – 3)
(3x+2)(5x-3)=10x^2
15x^2+x-6=10x^2
5x^2+x-6=0
(5x+6)(x-1)=0
x=-6/5
or
x=1