SOLUTION: solve for x; lnx+ln(x+1)=1

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Question 797274: solve for x; lnx+ln(x+1)=1
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
solve for x;
lnx+ln(x+1)=1
ln(x)(x+1)=1
e=x^2+x
x^2+x-e=0
solve for x by quadratic formula:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
a=1, b=1, c=-e
x=[-1±√(1-4*1*-e)]/2
x=[-1±√(1+4e)]/2