SOLUTION: A seventy foot long pipe is cut into three unequal pieces the second one is twice as long as the first piece the third piece is two feet longer than the first what the length of al
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-> SOLUTION: A seventy foot long pipe is cut into three unequal pieces the second one is twice as long as the first piece the third piece is two feet longer than the first what the length of al
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Question 797224: A seventy foot long pipe is cut into three unequal pieces the second one is twice as long as the first piece the third piece is two feet longer than the first what the length of all three pieces? Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! First piece = x
Second piece = 2x
3rd piece = x + 2
x + 2x + x + 2 = 70
Collect like terms:
4x = 70 - 2
4x = 68
x = 17
First piece = 17 feet.
Second piece = 34 feet.
Third piece = 19 feet.
Total = 70 feet.
Hope this helps.
:-)
