Question 797137: the length of a rectangle is thrice width. if the length is increase by 8 cm and width is increase by 2 cm, the perimeter of the new rectangle is 56 cm. find the dimension of the original rectangle.
Answer by mohanraj04(12)   (Show Source):
You can put this solution on YOUR website! ans:
given that the length(L) of rectangle is thrice width(W)
therefore, L=3W
when the length is increased by 8cm and width is increased by 2 cm, then the perimeter of the rectangle is 56cm
therefore, 2[(L+8)+(W+2)]=56
2[(3W+8)+(W+2)]=56 [since, L=3W ]
2[4W+10]=56
4W+10=56/2
4W+10=28
4W=28-10
4W=18
W=18/4
W=4.5cm
by L=3W
L=3*4.5 [ since, W=4.5cm ]
L=13.5cm
there fore the dimensions of the new rectangle are L=13.5cm & W=4.5cm
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