SOLUTION: m^2+4m-4=29 can you solve, please explain

Algebra ->  Expressions-with-variables -> SOLUTION: m^2+4m-4=29 can you solve, please explain      Log On


   

Question 79701: m^2+4m-4=29 can you solve, please explain
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
The standard equation is in the form of ax^2+bx+c=0.
The Quadratic equation below allows you to solve any equation of this form.
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
M^2+4M-4=29
M^2+4M-4-29=0
M^2+4M-33
USING THE QUADRATIC EQUATION WE GET
X=(-4+-SQRT[4^2-4*1*-33])/2*1
X=(-4+-SQRT[16+132])/2
X=(-4+-SQRT148)/2
X=(-4+-12.1655)/2
X=(-4+12.1655)/2
X=8.1655/2
X=34.083 ANSWER.
X=(-4-12.1655)/2
X=-16.1655/2
X=-8.083 ANSWER.