Question 79697This question is from textbook New York Math A semesters 1 & 2
: the larger of two intergers is 3 more than the smaller. If twice the square of the smaller interger is increased by 3 times the larger interger, the result is 23. Find the larger interger.
This question is from textbook New York Math A semesters 1 & 2
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! the larger of two integers is 3 more than the smaller.
smaller integer = x, and larger = (x+3)
:
If twice the square of the smaller integer is increased by 3 times the larger integer, the result is 23.
2x^2 + 3(x+3) = 23
:
Find the larger integer.
2x^2 + 3x + 9 = 23
:
2x^2 + 3x + 9 - 23 = 0
:
2x^2 + 3x - 14 = 0
:
(2x + 7)(x - 2) = 0
:
2x = -7,
x = -7/2 = -3.5; not an integer, so ignore this solution
and
x = +2, the larger integer: 2+3 = 5
:
Check using the statement,
"If twice the square of the smaller integer is increased by 3 times the larger integer, the result is 23."
;
2(2^2) + 3(5) = 23; solution checks out
:
Could you follow this OK?
|
|
|
