SOLUTION: if the perimeter of a rectangle is 52 ft and the width is 11 ft what is the length?
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Question 796841
:
if the perimeter of a rectangle is 52 ft and the width is 11 ft what is the length?
Answer by
waynest(281)
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length (L) = 11
width = w
2W + 2(11) = 52
2w + 22 = 52
2w + 22 - 22 = 52 - 22
2w = 30
2w/2 = 30/2
w = 15
check:
2(15) + 2(11) = 52
30 + 22 = 52
52 = 52