Question 796796: Without graphing, find the exact coordinates of the first maximum point to the right of the y-axis for y=4sin(2/3 x-pi/9)
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Without graphing, find the exact coordinates of the first maximum point to the right of the y-axis for y=4sin(2/3 x-pi/9)
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Equation for sin function:
y=Asin(Bx-C), A=amplitude, Period=2π/B, Period=C/B
For given function: y=4sin(2/3 x-pi/9)
Amplitude=4
B=2/3
Period=2π/B=2π/(2/3)=3π
1/4(period)=3π/4
C=π/9
Phase shift=C/B (shift to the right)=(π/9)/(2/3)=π/6
..
Without phase shift, the first maximum point occurs at 1/4 period at coordinates:(3π/4,4)
With phase shift of π/6, the first maximum point occurs at coordinates:(11π/12,4)
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