SOLUTION: how many gallons of a 90% antifreeze solution must be mixed with 70 gallons of 20% antifreeze to get a mixture that is 80% antifreeze

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Question 796685: how many gallons of a 90% antifreeze solution must be mixed with 70 gallons of 20% antifreeze to get a mixture that is 80% antifreeze
Answer by lwsshak3(11628) About Me  (Show Source):
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how many gallons of a 90% antifreeze solution must be mixed with 70 gallons of 20% antifreeze to get a mixture that is 80% antifreeze
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let x=amount of 90% solution to mix
70-x=amount of 20% solution to mix
..
90%x+20%(70-x)=80%*70
.9x+14-.2x=56
.7x=42
x=60
70-x=10
..
amount of 90% solution to mix=60 gal
amount of 20% solution to mix=10 gal