SOLUTION: This question came on the test as a bonus and i was really confused, so here it is 6x-2[2x-(10x+7)] please help and thanks. i have tried solving, but i do not think i am right, I

Algebra ->  Trigonometry-basics -> SOLUTION: This question came on the test as a bonus and i was really confused, so here it is 6x-2[2x-(10x+7)] please help and thanks. i have tried solving, but i do not think i am right, I      Log On


   



Question 796484: This question came on the test as a bonus and i was really confused, so here it is
6x-2[2x-(10x+7)] please help and thanks. i have tried solving, but i do not think i am right, I know you distribute the negative 1 which would give me 6x-2[2x(-10x-7)], then i removed my parenthesis that would be 6x-2[2x-10x-7], then i added 2x to -10x and got 6x-2[-8x-7]< so i removed the outer bars i don't why or what they called. 6x-2-8x-7 then i added 6x to -8x and got -2x and lastly added -2 to -7 and got -9 so my answer is -2x-9. so please help me and thanks

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
6x-2[2x-(10x+7)]
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= 6x-2[2x-10x-7]
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= 6x -2[-8x-7]
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= 6x + 16x + 14
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= 22x + 14
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Cheers,
Stan H.
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