SOLUTION: I have a question regarding a transformation of the "parent" absolute value function. I know that y < |x-2| would be the parent function with the vertex shifted 2 units to the rig

Algebra ->  Absolute-value -> SOLUTION: I have a question regarding a transformation of the "parent" absolute value function. I know that y < |x-2| would be the parent function with the vertex shifted 2 units to the rig      Log On


   



Question 796201: I have a question regarding a transformation of the "parent" absolute value function. I know that y < |x-2| would be the parent function with the vertex shifted 2 units to the right. I also know that y < -|x-2| would be the parent function with the vertex shifted 2 units to the right and reflected over the x-axis. I don't understand how to directly figure out the transformation of y < |-x-2|. I just feel like the negative sign is in the wrong place for the rules I know!
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
I have a question regarding a transformation of the "parent" absolute value function. I know that y < |x-2| would be the parent function with the vertex shifted 2 units to the right. I also know that y < -|x-2| would be the parent function with the vertex shifted 2 units to the right and reflected over the x-axis. I don't understand how to directly figure out the transformation of y < |-x-2|. I just feel like the negative sign is in the wrong place for the rules I know!
.
y < |-x-2|
rewrite as:
y < |-(x+2)|
The +2 shifts function 2 units left
The - REFLECTS over the Y-AXIS