SOLUTION: two cars pass each other traveling in opposite directions. One car is going 2.5 times as fast as the other car. At the end of 3.5 hours they are 490 apart find each cars rate. I
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Question 795930: two cars pass each other traveling in opposite directions. One car is going 2.5 times as fast as the other car. At the end of 3.5 hours they are 490 apart find each cars rate. I need some direction on this please. Thank you Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! two cars pass each other traveling in opposite directions.
One car is going 2.5 times as fast as the other car.
At the end of 3.5 hours they are 490 apart find each cars rate.
:
let s = speed of the slower car
then
2.5s = the speed of the faster
:
The relative speed is additive,
Write a distance equation, dist = time * speed
3.5(s + 2.5s) = 490
3.5s + 8.75s = 490
12.25s = 490
s = 490/12.25
s = 40 mph is the speed of the slower car
then
2.5(40) = 100 mph is the speed of the faster
