SOLUTION: 4. The Product of two consecutive odd integers is 58 less than the square of the next consecutive odd integer. Find the 3 integers.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: 4. The Product of two consecutive odd integers is 58 less than the square of the next consecutive odd integer. Find the 3 integers.      Log On


   



Question 795749: 4. The Product of two consecutive odd integers is 58 less than the square of the next consecutive odd integer. Find the 3 integers.
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
Let n be any integer.
The needed integers are 2n+1, 2n+3, 2n+5.

%282n%2B1%29%282n%2B3%29=-58%2B%282n%2B5%29%5E2 is the translated description.

Simplify and solve for n.

I omit the steps. You might think that a quadratic equation occur, but the n^2 term will be eliminated, and you will find ....
n=3.

The three integers are :
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2*3+1=7
9
and
11
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