SOLUTION: "A chemist needs 80 milliliters of a 27% solution but has only 17% and 33% solutions available. find how many milliliters of each that should be mixed to get the desired solution.

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: "A chemist needs 80 milliliters of a 27% solution but has only 17% and 33% solutions available. find how many milliliters of each that should be mixed to get the desired solution.      Log On


   

Question 795720: "A chemist needs 80 milliliters of a 27% solution but has only 17% and 33% solutions available. find how many milliliters of each that should be mixed to get the desired solution."
If you could please explain to me how i can find the equations, variables, essentially how to solve it i am completely at a loss, i have not idea how to find the equations/variables to be modeled by a system. Please and Thank You!
--Ashley
Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!
"A chemist needs 80 milliliters of a 27% solution but has only 17% and 33% solutions available. find how many milliliters of each that should be mixed to get the desired solution."
If you could please explain to me how i can find the equations, variables, essentially how to solve it i am completely at a loss, i have not idea how to find the equations/variables to be modeled by a system. Please and Thank You!
--Ashley

Let amount of 17% solution to be added be S
Since the mixture will sum to 80 mL, then amount of 33% solution to be added = 80 – S

Therefore, .17S + .33(80 – S) = .27(S + 80 – S)
.17S + 26.4 - .33S = 21.6
.17S - .33S = 21.6 – 26.4
- .16S = - 4.8

S, or amount of 17% solution to be added = %28-+4.8%29%2F-+.16, or highlight_green%2830%29 mL

Amount of 33% solution to be added = 80 – 30, or highlight_green%2850%29 mL

You can do the check!!

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