SOLUTION: the height of a righta regular class room has a perimeter of 28 m and area of 48m square. find the dimension of the classroom.

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Question 795512: the height of a righta regular class room has a perimeter of 28 m and area of 48m square. find the dimension of the classroom.

Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
Perimeter = 2*length + 2*width
28 m = 2l + 2w.........1
Area = length * width
48m = lw.............2
Altering Eq.(2)
48 m = lw
l = 48/w
Substitute l = 48/b into
Eq (2)
28m = 2l + 2w
28 = 2(48/w) + 2w
28 = 96/w + 2w
Common denominator = w
28w = 96 + 2w^2
2w^2 - 28w + 96 = 0
Divide thro'out by 2
x^2 - 14w + 48 = 0
(x - 8)(x - 6) = 0
x = 8, x = 6
Length = 8 m
Width = 6 m
OR
Length = 6 m
Width = 8 m
Hope this helps.
:-)