SOLUTION: A collection of nickels(x), dimes(y) and quarters(z) consist of 5 coins with a total of $0.55. If the number of dimes is equal to the number of nickels, find the number of each typ

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Question 795487: A collection of nickels(x), dimes(y) and quarters(z) consist of 5 coins with a total of $0.55. If the number of dimes is equal to the number of nickels, find the number of each type of coins.
There are.... nickels,....dimes, and .....quarters.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
(1) +x+=+y+
(2) +x+%2B+y+%2B+z+=+5+
(3) +5x+%2B+10y+%2B+25z+=+55+ ( in cents )
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You have 3 equations and 3 unknowns,
so it is solvable
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(2) +x+%2B+x+%2B+z+=+5+
(2) +z+=+5+-+2x+
----------------------
(3) +5x+%2B+10x+%2B+25%2A%28+5+-+2x+%29+=+55+
(3) +15x+%2B+125+-+50x+=+55+
(3) +-35x+=+-70+
(3) +x+=+2+
and also,
(1) +y+=+x+
(1) +y+=+2+
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(2) +x+%2B+y+%2B+z+=+5+
(2) +2+%2B+2+%2B+z+=+5+
(2) +z+=+1+
There are 2 nickels, 2 dimes, and 1 quarter