SOLUTION: how to solve this. 400 pounds of a clay with 1% water. Another clay with 2% is available. How much of 2% clay must you mix with 400 pounds of 1% clay get a 1.4% clay. How much 1.4%

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: how to solve this. 400 pounds of a clay with 1% water. Another clay with 2% is available. How much of 2% clay must you mix with 400 pounds of 1% clay get a 1.4% clay. How much 1.4%      Log On

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Question 795468: how to solve this. 400 pounds of a clay with 1% water. Another clay with 2% is available. How much of 2% clay must you mix with 400 pounds of 1% clay get a 1.4% clay. How much 1.4% clay will you end up?

Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
how to solve this. 400 pounds of a clay with 1% water. Another clay with 2% is available. How much of 2% clay must you mix with 400 pounds of 1% clay get a 1.4% clay. How much 1.4% clay will you end up?
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Equation::
clay + clay = clay
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0.99*400 + 0.98x = 0.986(400+x)
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990*400 + 980x = 986*400 + 986x
6x = 4*400
x = 266.67 lbs
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Ans: 666.67 lbs
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Cheers,
Stan H.
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Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = pounds of 2% clay needed
+.02x+ = pounds of water in 2% clay
+.01%2A400+=+4+ pounds of water in 1% clay
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+%28+.02x+%2B+4+%29+%2F+%28+x+%2B+400+%29=+.014+
+.02x+%2B+4+=+.014%2A%28+x+%2B+400+%29+
+.02x+%2B+4+=+.014x+%2B+5.6+
+.006x+=+1.6+
+x+=+1.6%2F.006+
+x+=+266.667+
You end up with +x+%2B+400+ pounds of
the 1.4% clay
+x+%2B+400+=+666.667+ pounds
check answer:
+%28+.02x+%2B+4+%29+%2F+%28+x+%2B+400+%29=+.014+
+%28+.02%2A266.667+%2B+4+%29+%2F+%28+266.667+%2B+400+%29=+.014+
++5.333+%2B+4+=+.014%2A666.667+
+9.333+=+9.333+
OK