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Question 795396: x+3= sqrt (1-3x)
First i squared both sides of the equation and got
x^2+6x+9=1-3x
Then i knew i had to factor because it was a quadratic so I put everything to one side of the equal sign so it equalled zero, i got
x^2+9x+8
I think i went wrong somewhere because I cannot factor that equation
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! x+3= sqrt (1-3x)
First i squared both sides of the equation and got
x^2+6x+9=1-3x
Then i knew i had to factor because it was a quadratic so I put everything to one side of the equal sign so it equalled zero, i got
x^2+9x+8
I think i went wrong somewhere because I cannot factor that equation
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Equations are not factored, equations are solved.
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x^2+9x+8 = 0
(x + 1)*(x + 8) = 0
You were almost home.
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