SOLUTION: A collection of nickels (x), dimes (y), and quarters (z) consist of 85 coins with a total of $10.25. If there are 2 times as many dimes as quarters, find the number of each type.
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Question 795376: A collection of nickels (x), dimes (y), and quarters (z) consist of 85 coins with a total of $10.25. If there are 2 times as many dimes as quarters, find the number of each type. Answer by sunny1992(35) (Show Source):
You can put this solution on YOUR website! 1 nickel = 5cents
1 dime = 10cents
1 quarter = 25 cents
$10.25 = 1025 cents
x+y+z = 85 -----> eq1
5x+10y+25z = 1025 ----> eq2
y=2z
putting y=2z in eq 1
x+2z+z=85
x+3z=85
x=85-3z
putting x=85-3z & y=2z in eq 2
5(85-3z)+10(2z)+25z=1025
425-15z+20z+25z=1025
30z=1025-425
30z=600
z=20
y=2z=2(20)=40
x=85-3z=85-3(20)=25
