SOLUTION: I need help on a proprtion, 2u-3/4u=u-1/u I did cross product method on this one and i got 2u(squared)-3u= 4u (squared)-4u then i isolated the u and the u (squared) and c

Algebra ->  Proportions -> SOLUTION: I need help on a proprtion, 2u-3/4u=u-1/u I did cross product method on this one and i got 2u(squared)-3u= 4u (squared)-4u then i isolated the u and the u (squared) and c      Log On


   



Question 795: I need help on a proprtion,
2u-3/4u=u-1/u I did cross product method on this one and i got
2u(squared)-3u= 4u (squared)-4u then i isolated the u and the u (squared) and came out with u=2u(squared). I think i did this all right, but i'm not sure what the u would be. I missed this lesson in math becuase i'm on homebound school because of an illness i have. If you can please help me out i would appreciate it. Thank You.

Found 3 solutions by pushpaharan, JimMarshall, MathTherapy:
Answer by pushpaharan(47) About Me  (Show Source):
You can put this solution on YOUR website!
2u-3/4u=u-1/u
2u-u = 1/u+3/4u
u= 7/4u
u^2 = 7/4
u= Sqrt(7/4) = 1.32

Answer by JimMarshall(82) About Me  (Show Source):
You can put this solution on YOUR website!
2u-3/4u=u-1/u
2u-u = 1/u+3/4u
u= 7/4u
u^2 = 7/4
u= Sqrt(7/4) = 1.32 Ans

Answer by MathTherapy(10551) About Me  (Show Source):
You can put this solution on YOUR website!

I need help on a proprtion,
2u-3/4u=u-1/u I did cross product method on this one and i got
2u(squared)-3u= 4u (squared)-4u then i isolated the u and the u (squared) and came out with u=2u(squared). I think i did this all right, but i'm not sure what the u would be. I missed this lesson in math becuase i'm on homebound school because of an illness i have. If you can please help me out i would appreciate it. Thank You.
It appears as though you mean: %282u+-+3%29%2F%284u%29+=+%28u+-+1%29%2Fu, with u+%3C%3E+0. If so, you need to use PARENTHESES next time
%282u+-+3%29%2F%284u%29+=+%28u+-+1%29%2Fu
u(2u - 3) = 4u(u - 1) ------- Cross-multiplying
2u%5E2+-+3u+=+4u%5E2+-+4u
4u%5E2+-+2u%5E2+-+4u+%2B+3u+=+0
2u%5E2+-+u+=+0 ------- You're correct up to this point.
u%282u+-+1%29+=+0
2u - 1 = 0 OR u = 0 (ignore)
2u = 1
highlight_green%28u+=+1%2F2%29