SOLUTION: 1. At noon a private plane left austin for los angeles,2100km away, flying at 500km/hr. one for austin at 700km/hr. at what time did they pass each other?

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: 1. At noon a private plane left austin for los angeles,2100km away, flying at 500km/hr. one for austin at 700km/hr. at what time did they pass each other?      Log On


   



Question 79463This question is from textbook
: 1. At noon a private plane left austin for los angeles,2100km away, flying at 500km/hr. one for austin at 700km/hr. at what time did they pass each other? This question is from textbook

Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
500T+700T=2100
1200T=2100
T=2100/1200
T=1.75 HOURS AFTER THEY LEAVE THEY PASS EACH OTHER.
PROOF
500*1.75+700*1.75=2100
875+1225=2100
2100=2100