SOLUTION: 5/2=P+12 /2p can i please get the working and answer

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Question 794086: 5/2=P+12 /2p can i please get the working and answer
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Maybe you meant 5/2=(p+12)/2p, which is the proper way to write 5%2F2=%28p%2B12%29%2F%222+p%22 on just one line.
Or maybe you really meant 5/2=p+12/2p, which can be written as 5%2F2=p%2B12%2F%222+p%22.
Or maybe there were two variables: P and p.
I'll try to answer the first two options:

To solve 5%2F2=%28p%2B12%29%2F%222+p%22
I know that p cannot be zero, because to expression on the right side does not exist when p=0.
I would start by multiplying both side times 2p to get rid of denominators.
I get the equivalent equation
5%2A2p%2F2=2p%2A%28p%2B12%29%2F%222+p%22-->5p=p%2B12
Next, I subtract p from both sides of the equal sign to get the equivalent equation
5p-p=p%2B12-p-->5p-p=12-->4p=12
Finally, I divide both sides of the equation by 4 to get
4p%2F4=12%2F4-->p=12%2F4-->highlight%28p=3%29

To solve 5%2F2=p%2B12%2F%222+p%22, I first simplify:
5%2F2=p%2B12%2F%222+p%22-->5%2F2=p%2B6%2Fp.
I know that p cannot be zero, because to expression on the right side does not exist when p=0.
I would start by multiplying both side times 2p to get rid of denominators.
I get 2p%2A5%2F2=2p%28p%2B12%2F%222+p%22%29-->5p=2p%2Ap%2B12-->5p=2p%5E2%2B12-->2p%5E2-5p%2B12=0
Unfortunately, that equation does not have any real solution.