SOLUTION: how do you solve 7(3x +4)= 8(2x +5) +13

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Question 79406: how do you solve 7(3x +4)= 8(2x +5) +13
Answer by tutorcecilia(2152) About Me  (Show Source):
You can put this solution on YOUR website!
7(3x +4)= 8(2x +5) +13 [use the distributive property to multiply]
21x+28=16x+40+13 [combine like-terms if possible]
21x+28=16x+53 [solve for the x-term]
21x-16x+28=16x-16x+53
5x+28=53
5x+28-28=53-28
5x=25
5x/5=25/5
x=5
.
check by plugging (x=5) back into the orignial eqution and solve]
7(3x +4)= 8(2x +5) +13
7[3(5) +4]= 8[2(5) +5] +13
133=133 [checks out]