SOLUTION: (3a^2)^2(a^3 + 4)^2.....This problem is dealing with power of exponents.
for my answer...I got 9a^2(2a^3 + 16), and it is wrong.
How do I solve this problem correctly?
Tha
Algebra ->
Exponents-negative-and-fractional
-> SOLUTION: (3a^2)^2(a^3 + 4)^2.....This problem is dealing with power of exponents.
for my answer...I got 9a^2(2a^3 + 16), and it is wrong.
How do I solve this problem correctly?
Tha
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Question 793915: (3a^2)^2(a^3 + 4)^2.....This problem is dealing with power of exponents.
for my answer...I got 9a^2(2a^3 + 16), and it is wrong.
How do I solve this problem correctly?
Thank you for your time Answer by sunny1992(35) (Show Source):
You can put this solution on YOUR website! (3a^2)^2 (a^3+4)^2
let solve bracket wise
bracket 1
(3^2 a^2x2)
9a^4
bracket 2
here we will use (a+b)^2 = a^2+2ab+b^2
(a^3)^2+2(a^3)(4)+(4)^2
a^6+8a^3+16
answer=
if factorize = (9a^4)(a^6+8a^3+16)
if simplify= 9a^10+72a^7+144a^4
i hope the answer is one of the above
