Question 793819: If cos(t)=4/5, evaluate (i)cos(pi-t) and (ii)cos(t+pi)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! If cos(t)=4/5,
-----
cos = x/r so x = 4 and r = 5
The y = sqrt[5^2-4^2] = 3
So, sin(t) = y/4 = 3/5
===============================
Evaluate
(i)cos(pi-t) = cos(pi)*cos(t)+sin(pi)*sin(t)
= (-1)*(4/5) + (3/5)*0
= -4/5
============================
(ii)cos(t+pi) = cos(t)*cos(pi) - sin(t)*sin(pi)
= (4/5)(-1) - (3/5)(0)
= -4/5
============================
Cheers,
Stan H.
==============
|
|
|
