SOLUTION: Find two consecutive odd integers if three times the smallest integer is 7 more than twice the largest integer
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Question 793573
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Find two consecutive odd integers if three times the smallest integer is 7 more than twice the largest integer
Answer by
CubeyThePenguin(3113)
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consecutive odd integers: x, (x+2)
3x = 7 + 2(x+2)
3x = 2x + 11
x = 11
The integers are 11 and 13.