SOLUTION: a regular pentagon I inscribed in a circle whose radius is 9 in. find the area of the pentagon

Algebra ->  Parallelograms -> SOLUTION: a regular pentagon I inscribed in a circle whose radius is 9 in. find the area of the pentagon      Log On


   



Question 793226: a regular pentagon I inscribed in a circle whose radius is 9 in. find the area of the pentagon
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Here is your pentagon (in red), with the circle, and the radii to the pentagon vertices (in green).
Those radii split the pentagon into 5 congruent isosceles triangles.
The area of a triangle can be calculated as a%2Ab%2Asin%28C%29 if you know the measures of sides a and b and angle C between those two sides.
In this case, two of the sides are the radii, measuring 9in, and the angle between them measures 72%5Eo.
The area of one of those triangles is
%289in%29%2A%289in%29%2Asin%2872%5Eo%29= approx. 81%2A0.951in%5E2=77in%5E2
The area of the pentagon is approximately 5%2A77in%5E2=385in%5E2