SOLUTION: how do you find the solution to y=x^2+2x+1
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Question 793219
:
how do you find the solution to
y=x^2+2x+1
Answer by
waynest(281)
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factor:
x^2 + 2x + 1 = y
(x + 1)^2 = y
x + 1 = 0
x + 1 - 1 = 0 - 1
x = -1
check:
(-1)^2 + 2(-1) + 1 = 0
1 - 2 + 1 = 0
0 = 0