SOLUTION: please help me with the answer on: 1) Find four 3-digit numbers whose average is greater than two of them? 2) Find four 3-digit numbers whose average is greater then three of the

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Question 793194: please help me with the answer on:
1) Find four 3-digit numbers whose average is greater than two of them?
2) Find four 3-digit numbers whose average is greater then three of them?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
1) 101, 199, 102, and 198
The average of the first two, the average of the last two, and the average of all four is 150, which is greater than 101 and 102.
I made the pairs so they would add up to 300:
101+199=300 and 102+198=300
Actually, I started with 1 and 99, which add up to 100 and average 50, but added 100 to each to make then 3-digit numbers.

2) 101, 102, 103, and 194
The average is 125, which is greater than 101, 102, and 103.
I first thought of 1, 2, 3, and 100-(1+2+3)=100-6=94 to get four numbers adding to 100, which would make the average 25. Then, I added 100 to each to make them 3 digits long.