SOLUTION: I have to find the coordinates of the vertex. and then sketch the graph...
the problem is:
y=x^2+6x+12
I'm assuming the x^2 means x sq?
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-> SOLUTION: I have to find the coordinates of the vertex. and then sketch the graph...
the problem is:
y=x^2+6x+12
I'm assuming the x^2 means x sq?
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Question 79260: I have to find the coordinates of the vertex. and then sketch the graph...
the problem is:
y=x^2+6x+12
I'm assuming the x^2 means x sq? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! find the coordinates of the vertex. and then sketch the graph...
the problem is:
y=x^2+6x+12
You have a quadratic with a=1, b=6
The vertex is at x=-b/2a=-6/2=-3
The y value when x=-3 is (-3)^2+6*(-3)+12 = 3
The vertex is at (-3,3)
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Cheers,
Stan H.
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