Question 792386: At the end of 2010, 31% of the households in the Us had a Blu-ray player. If eight households are chosen at random, find the probability that
a.Exactly five of them have a Blu-ray.
b. At least five of them have a Blu-ray player.
c. At most four of them have a Blu-ray player.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! At the end of 2010, 31% of the households in the Us had a Blu-ray player. If eight households are chosen at random,
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Binomial Problem with n = 8 and p(have) = 0.31
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find the probability that
a.Exactly five of them have a Blu-ray.
P(x = 5) = 8C5(0.31)^5*(0.69)^3 = binompdf(8,0.31,5) = 0.0527
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b. At least five of them have a Blu-ray player.
P(5<= x <=8) = 1 - P(0<= x <=4) = 1 - binomcdf(8,0.31,4) = 0.0661
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c. At most four of them have a Blu-ray player.
Ans: 1-binomcdf(8,0.31,3) = 0.2126
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Cheers,
Stan H.
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