SOLUTION: Suppose that you have 8 cards. 5 are green and 3 are yellow. The 5 green cards are numbered 1,2,3,4,5 and the yellow cards are number 1,2,3. You randomly draw two cards, one at a t
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-> SOLUTION: Suppose that you have 8 cards. 5 are green and 3 are yellow. The 5 green cards are numbered 1,2,3,4,5 and the yellow cards are number 1,2,3. You randomly draw two cards, one at a t
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Question 792324: Suppose that you have 8 cards. 5 are green and 3 are yellow. The 5 green cards are numbered 1,2,3,4,5 and the yellow cards are number 1,2,3. You randomly draw two cards, one at a time, with replacement.
a. P(G1 AND G2)
B. P (at least one green)
c. P (G2|G1)
D. Are these independent events?
e. Draw a tree diagram.
**I keep getting 5/8 for the answers...I need to double check myself. It doesn't seem right.
Thanks. Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! a) 1/8 * 1/8 = 1/64 P(G1 AND G2) If they must be picked in that order.
1/32 if they are picked in any order.
.
b)
3/8 * 3/8 = 9/64 Probability both are yellow.
1 - 9/64 = 55/64 P (at least one green)
.
c) 0 If the sample space is G1 you can't get G2
.
Yes
.
Ed
