SOLUTION: find all sets of 3 consecutive even integers whose sum is greater than 102 but less than 116

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Question 791862: find all sets of 3 consecutive even integers whose sum is greater than 102 but less than 116
Answer by CubeyThePenguin(3113) About Me  (Show Source):
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consecutive even integers: (x-2), x, (x+2) ----> x denotes the middle number

102 < (x-2) + x + (x+2) < 116
102 < 3x < 116
34 < x < 38.666

integer solutions of x: 35, 36, 37, 38

corresponding sets of integers: (34, 35, 36), (35, 36, 37), (36, 37, 38), (37, 38, 39)