Question 791828: Bob is a real state agent who travels to different neighborhoods to meet clients. The real estate company reimburses him for these expenses at the end of each month. Bob is allowed $0.45 per km for mileage and $9 per day for phone calls. In June, his mileage, meals, and phone expenses totalled $599.
Bobs mileage claim was $80 more than his claim for telephone calls, and his claim for meals for $20 less than his mileage claim. How far did Bob drive in June?
Im not even sure where to begin. Please help!
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Bob is allowed $0.45 per km for mileage and $9 per day for phone calls.
In June, his mileage, meals, and phone expenses totaled $599.
:
Let m = the no. of miles driven
let t = amt of telephone calls
let f = amt for meals
therefore
.45m + t + f = 599
:
Write an equation for the following statements:
:
Bobs mileage claim was $80 more than his claim for telephone calls,
.45m = t + 80
we can rewrite this to
t = .45m - 80
:
his claim for meals for $20 less than his mileage claim.
f = .45m - 20
:
Going back to the first equation, substitute for t and f:
.45m + (.45m-80) + (.4m-20) = 599
combine like terms
.45m + .45m + .45m - 80 - 20 = 599
1.35m - 100 = 599
1.35m = 599 + 100
1.35m = 699
m = 699/1.35
m ~ 518 miles in June
:
:
To check this, find the amt for mileage: 518 * .45 ~ $233
then
233 + (233-80) + 233-20) =
233 + 153 + 213 = 599
:
Did we make some sense out this for you? Always begin by defining the variables, in this case m, t, f; then write an equation for each statement.
Arrange these equations so you can substitute in a manner that will let you deal with one variable. CK
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