SOLUTION: Topic: Solving/Factoring Quadratic Expressions (Word Problems) Question: The area of a rectangle is twice the area of a square. If the rectangle is 6 inches long, and the width of

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: Topic: Solving/Factoring Quadratic Expressions (Word Problems) Question: The area of a rectangle is twice the area of a square. If the rectangle is 6 inches long, and the width of      Log On


   

Question 791811: Topic: Solving/Factoring Quadratic Expressions (Word Problems)
Question: The area of a rectangle is twice the area of a square. If the rectangle is 6 inches long, and the width of the rectangle is the same as the length of a side of the square, find the dimensions of both the rectangle and the square.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
rectangle dimensions: 6 inches long, x inches wide

square dimensions: x inches long, x inches wide

6x = 2(x^2)
6x = 2x^2
3x = x^2
0 = x^2 - 3x
0 = x(x - 3)

x has to be positive ---> x = 3

rectangle is 6 inches long and 3 inches wide, square has side length 3 inches