SOLUTION: log of 18 to the base 12=a and log of 54 to the base 24=b then 5(a-b)+ab is?

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Question 791626: log of 18 to the base 12=a and log of 54 to the base 24=b then 5(a-b)+ab is?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
log of 18 to the base 12=a
log%2812%2C18%29+=+a
exponent equiv of logs
12%5Ea+=+18
a*log(12) = log(18)
a = log%2818%29%2Flog%2812%29
a = 1.16317
and
log of 54 to the base 24=b
log%2824%2C54%29+=+b
24%5Eb+=+54
b*log(24) = log(54)
b = log%2854%29%2Flog%2824%29
b = 1.25517
:
then 5(a-b) + ab is?
5(1.16317 - 1.25517) + (1.16317*1.25517) = ?, leave this math for you
see if you get about 1