SOLUTION: I tried to do 1/( (SQRT2)-3) I multiplyed the numerator and the denominator by -3-(SQRT2) and I got -3-(SQRT2)/-14 but my teacher said it was wrong. What did I do wrong? Please

Algebra ->  Radicals -> SOLUTION: I tried to do 1/( (SQRT2)-3) I multiplyed the numerator and the denominator by -3-(SQRT2) and I got -3-(SQRT2)/-14 but my teacher said it was wrong. What did I do wrong? Please      Log On


   



Question 791483: I tried to do 1/( (SQRT2)-3)
I multiplyed the numerator and the denominator by -3-(SQRT2) and I got
-3-(SQRT2)/-14 but my teacher said it was wrong. What did I do wrong?
Please help

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


You selected a mathematically correct form of the conjugate of the denominator to form your multiplier, but then you must have done the arithmetic incorrectly because for your denominator calculation.

Personally, I would have created the conjugate by simply changing the sign on the second term of the binomial. My "times 1" multiplier would have been . My final answer would have come out to be:



which is equivalent to the answer you would have had given correct arithmetic. Go back and recheck your calculations.

John

My calculator said it, I believe it, that settles it
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