SOLUTION: I tried to do 1/( (SQRT2)-3)
I multiplyed the numerator and the denominator by -3-(SQRT2) and I got
-3-(SQRT2)/-14 but my teacher said it was wrong. What did I do wrong?
Please
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-> SOLUTION: I tried to do 1/( (SQRT2)-3)
I multiplyed the numerator and the denominator by -3-(SQRT2) and I got
-3-(SQRT2)/-14 but my teacher said it was wrong. What did I do wrong?
Please
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Question 791483: I tried to do 1/( (SQRT2)-3)
I multiplyed the numerator and the denominator by -3-(SQRT2) and I got
-3-(SQRT2)/-14 but my teacher said it was wrong. What did I do wrong?
Please help Answer by solver91311(24713) (Show Source):
You selected a mathematically correct form of the conjugate of the denominator to form your multiplier, but then you must have done the arithmetic incorrectly because for your denominator calculation.
Personally, I would have created the conjugate by simply changing the sign on the second term of the binomial. My "times 1" multiplier would have been . My final answer would have come out to be:
which is equivalent to the answer you would have had given correct arithmetic. Go back and recheck your calculations.
John
My calculator said it, I believe it, that settles it