SOLUTION: Find the coordinates of the vertex and the equation of the axis of symmetry of the graph of the eqution. y=6+4x-1/2 x squared

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Question 79140This question is from textbook Algebra:Structure and Method
: Find the coordinates of the vertex and the equation of the axis of symmetry of the graph of the eqution. y=6+4x-1/2 x squared This question is from textbook Algebra:Structure and Method

Answer by stanbon(75887) About Me  (Show Source):
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Find the coordinates of the vertex and the equation of the axis of symmetry of the graph of the eqution. y=6+4x-1/2 x squared
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Put the equation in vertex form:
-1/2 x^2 +4x = y-6
(-1/2)(x^2- 8x + 4^2) = y-6-(1/2)*16
(-1/2)(x-4)^2= y-14
Vertex at x=4,y=14
Axis of symmetry is x=4
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graph%28400%2C300%2C-10%2C20%2C-10%2C20%2C%28-1%2F2%29x%5E2%2B4x%2B6%29
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Cheers,
Stan H.