SOLUTION: {{{x+6y=2}}} {{{5x+4y=36}}} I have been trying to use substitution to solve the system. I do as I was taught and on the first equation subtract 6y from both sides to find my X

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: {{{x+6y=2}}} {{{5x+4y=36}}} I have been trying to use substitution to solve the system. I do as I was taught and on the first equation subtract 6y from both sides to find my X       Log On


   

Question 791320: x%2B6y=2
5x%2B4y=36
I have been trying to use substitution to solve the system. I do as I was taught and on the first equation subtract 6y from both sides to find my X equation. Every time I plug in x=2-6y I keep getting y=0 which is not correct because I have checked. I also get x=2. No matter how many times I work it the answer is still the same. I would like to know how you get the correct answer, which is in the back of my math book, (8, -1) Thank you.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
solve the first equation for x to get

x+6y=2

x=2-6y

then plug this into the second equation

5x+4y=36

5(2 - 6y)+4y=36

10 - 30y+4y=36

10-28y=36

-26y=36-10

-26y=26

y = 26/(-26)

y = -1

And then use this to find x

x=2-6y

x=2-6(-1)

x=2+6

x = 8

So that shows you why the answer is (8,-1)