SOLUTION: Graph the circle (x-2)^2+(y+1)^2=16 and plot and label a point 'C' at the center and what are the coordinates of 'C'

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Graph the circle (x-2)^2+(y+1)^2=16 and plot and label a point 'C' at the center and what are the coordinates of 'C'      Log On


   



Question 791285: Graph the circle (x-2)^2+(y+1)^2=16 and plot and label a point 'C' at the center and what are the coordinates of 'C'
Answer by DrBeeee(684) About Me  (Show Source):
You can put this solution on YOUR website!
Given the circle
(1) %28x-2%29%5E2+%2B+%28y%2B1%29%5E2+=+16
The x coordinate of the center point C(x,y) is given by
(2) x-2 = 0 or
(3) x = 2
The y coordinate of C is given by
(4) y+1 = 0 or
(5) y = -1
The center of the circle is at the point C(2,-1)
The radius squared is 16, so we can get the radius from
(6) r^2 = 16 or
(7) r = 4
To graph you can use a graphics calculator or use a compass with point at (2,-1) and spread a "distance" of 4 and scribe the circle.