Question 79123: The numbers 1 to 10 are written on sheets of paper and placed in a hat. If two sheets are selected at random then find the following:
The probabilit both numbers are ODD with replacement.
Note: "with replacement" assumes the first selection is replaced back into the hat before the second selection is made.
A. 1/100
B. 1/4
C. 2/9
D. 1/5
The probability both numbers are ODD without replacement.
Note: "without replacement" assumes the first selection is NOT replaced back into the hat, but is held out, while the second selection is made.
A. 1/5
B. 2/9
C. 1/4
D. 1/100
The probability the first number is ODD and the second number is EVEN without replacement.
A. 1/4
B. 5/18
C. 2/9
D. 13/18
The probability of selecting a 2 and then a 9, with replacement.
A 1/4
B. 5/18
C. 2/9
D. 13/18
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The numbers 1 to 10 are written on sheets of paper and placed in a hat. If two sheets are selected at random then find the following:
The probabilit (both numbers are ODD with replacement)=(5/10)(5/10)=1/4
Note: "with replacement" assumes the first selection is replaced back into the hat before the second selection is made.
A. 1/100
B. 1/4
C. 2/9
D. 1/5
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The probability (both numbers are ODD without replacement)=(5/10)(4/9)=2/9
Note: "without replacement" assumes the first selection is NOT replaced back into the hat, but is held out, while the second selection is made.
A. 1/5
B. 2/9
C. 1/4
D. 1/100
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The probability (the first number is ODD AND the second number is EVEN without replacement) = (5/10)(5/9)=25/90=5/18
A. 1/4
B. 5/18
C. 2/9
D. 13/18
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The probability
(of selecting a 2 and then a 9, with replacement)=(1/10)(1/10)=1/100
A 1/4
B. 5/18
C. 2/9
D. 13/18
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Cheers,
Stan H.
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