SOLUTION: at 1:00 p.m., a car leave a city and travels north at a rate of 55mi/h. An hour later, a second care leaves the city and travels south at a rate of 60 mi/hr. At what time will th
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Question 79115: at 1:00 p.m., a car leave a city and travels north at a rate of 55mi/h. An hour later, a second care leaves the city and travels south at a rate of 60 mi/hr. At what time will the two cars be 285 miles apart? Found 2 solutions by checkley75, josmiceli:Answer by checkley75(3666) (Show Source):
You can put this solution on YOUR website! 55T+60(T-1)=285
55T+60T-60=285
115T=285+60
115T=345
T=345/115
T=3 HOURS AFTER THE FIRST CAR LEAVES THEY WILL BE 285 MILES APART.
PROOF:
55*3+60*2=285
165+120=285
285=285
You can put this solution on YOUR website! The way to read this is that the sum of the distances the cars travel
is 285 mi.
I'd like to start them both off at the same time, so the 2nd car has gone mi when the 1st car begins to move.
They travel for the same amount of time now, so hrs
The time will be 1 pm + 1 hr + 45/23 hrs
This is 1 pm + 3 hrs - 1/23 hrs, or
4 pm - 1/23*60 min, or
3 pm + 57.4 min
I hope I didn't make a mistake
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