SOLUTION: How do I simplify: [sin(b + pi)]/[sin (b)] thanks!

Algebra ->  Trigonometry-basics -> SOLUTION: How do I simplify: [sin(b + pi)]/[sin (b)] thanks!      Log On


   

Question 790863: How do I simplify: [sin(b + pi)]/[sin (b)]
thanks!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
[sin(b + pi)]/[sin (b)]

[sin(b)cos(pi) + cos(b)sin(pi)]/[sin (b)]

[sin(b)(-1) + cos(b)(0)]/[sin (b)]

[-sin(b) + 0]/[sin (b)]

[-sin(b)]/[sin (b)]

-1

-------------------------------------------------------

So [sin(b + pi)]/[sin (b)] = -1 for all allowed values of b in the domain.