There is a factor of 5 and three factors of x in the numerator. There is a factor of 3, a factor of 5, one factor of x, and 3 factors of y in the denominator. The numerator and denominator have a factor of 5 and one factor of x in common. Eliminate the common factors:
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it