SOLUTION: sqrt(x+3) = x - 3
I eliminated the square root by squaring both sides and got:
x + 3 = x^2 -6x +9
Combining like terms and putting into quadratic equation:
0 = x^2 -7x -6
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: sqrt(x+3) = x - 3
I eliminated the square root by squaring both sides and got:
x + 3 = x^2 -6x +9
Combining like terms and putting into quadratic equation:
0 = x^2 -7x -6
Log On
Question 790558: sqrt(x+3) = x - 3
I eliminated the square root by squaring both sides and got:
x + 3 = x^2 -6x +9
Combining like terms and putting into quadratic equation:
0 = x^2 -7x -6
No two numbers satisfy the above, and I couldn't solve it via the quadratic formula. What do I do next?
Thanks in advance. Found 2 solutions by rfer, solver91311:Answer by rfer(16322) (Show Source):
Work it out again, paying very careful attention to your signs this time and see if you don't end up with
Which does, indeed, factor quite tidily.
Why you were unable to solve the incorrect equation using the quadratic formula is a mystery. It should have worked fine giving two real number zeros. You always will have two real number zeros if the signs on a and c are opposite.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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