Slope intercept form of a line is y=mx+b where m is the slope.
Parallel lines have = slopes. y=2x-8 has a slope, m = 2. So the slope of the parallel line is 2.
The point slope form of a graph is y-y(1) = m(x-x(1)) where x(1),y(1) is a point on the line. The problem states (-1,3) is on the line.
We know the slope, 2, and the point (x(1),y(1)) = (-1,3)
y-3 = 2(x-(-1) = y-3 = 2(x+1) = y-3 = 2x + 2
y = 2x + 5
(