Question 790009: Stuck need help with this problem:
A chemist needs a 110 mL of 32% solution, but only has 29% & 40% solutions available. How much of each solution does he need?
Can you please walk me thru this to help me get the answer?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618)   (Show Source):
You can put this solution on YOUR website! {amount of dissolved component}/{amount of resulting solution}={concentration of dissolved component}
AND
{sum of quantities of all solutions} = {total amount of resulting solution}
x = volume of 29% solution
y = volume of 40% solution
 and 
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website!
Stuck need help with this problem:
A chemist needs a 110 mL of 32% solution, but only has 29% & 40% solutions available. How much of each solution does he need?
Can you please walk me thru this to help me get the answer?
Let amount of 29% to be used be T
Then amount of 40% to be used = 110 T
Therefore, .29T + .4(110 T) = .32(T + 110 T)
.29T + 44 - .4T = .32T + 35.2 - .32T
.29T - .4T = 35.2 44
- .11T = - 8.8
T, amount of 29% solution to be used =  , or  , or  mL
Amount of 40% solution to be used = 110 - 80, or  mL
You can do the check!!
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