SOLUTION: Having trouble with this concept.Category is "replacement sets" the question posed is- b-(-3b-3)=4b+3.the correct set is 2.....but then the confusion with me is-again-2-(-6-3) whic
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Question 789983: Having trouble with this concept.Category is "replacement sets" the question posed is- b-(-3b-3)=4b+3.the correct set is 2.....but then the confusion with me is-again-2-(-6-3) which is-2-(-9)=11? the other side of equation is ok(11 of course).Is it because the 2 negative signs(one inside parenthesis)and the positive 2 in front makes the 9 positive???? One final question-any number inside absolute value sign will become positive-if the number is negative....but positive number cannot become negative? Found 2 solutions by solver91311, MathLover1:Answer by solver91311(24713) (Show Source):
So what is the problem here? Either 2 is NOT the correct replacement set, or that minus sign you have in front of the 2 in the LHS of your equation is spurious.
If the problem is
Then
And that is true no matter what value you substitute for , so 2 would work just fine as in:
But it would work just as well if
But if the problem is
Then
Which is only true if
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
as you said, the other side of equation is ok(11 of course).Is it because the 2 negative signs(one inside parenthesis)and the positive 2 in front makes the 9 positive--this is
now, your question: any number inside absolute value sign will become positive-if the number is negative
that is ; recall definition of absolute value
the absolute value of a number is the the number is (on a number line}}}
example: , on number line is units to the left from zero , on number line is units to the right from zero